An element S (Z-?, A-?) to R (Z-85,A-222) after emitting 2α-particles and 1β-paticle. Find the atomic number. and mass number of the element S.
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Answer:
Explanation:
On emission of 2 alpha particles, mass number is reduced by 8 and atomic number by 4.
z
S
A
→
z−4
Q
A−8
+2
2
He
4
Now, on emission of 1 beta particle, mass number remains same but atomic number increases by 1.
z−4
Q
A−8
→
z−8
R
A−8
+
−1
0
β
After decay, given element is
85
R
222
.
Therefore,
A−8=222⇒A=230
(Atomic Mass)
Z−3=85⇒Z=88
(Atomic Number)
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