an element x has 3 electons in its outermost third orbit
(a) what will be its atomic number and number of proton in it
(b) write its electronic configuration?
Answers
Answered by
2
Number of electrons in element x= 2+8+3=13 electrons
Atomic no. = No. of electrons= No. Of protons= 13
Electronic configuration that's the arrangement of electrons will be=
2, 8, 3
Atomic no. = No. of electrons= No. Of protons= 13
Electronic configuration that's the arrangement of electrons will be=
2, 8, 3
Similar questions