Question

An element 'X' has mass no 32 and atomic no 16.Find
1.The number of neutrons in the neucleas
2.The number of electron in the outermost shell of the atom
3.The electronic configuration of x and find the valency

Answer 1

Mass no A = 32= no. of neutrons + no. of protons. but as atomic no. is 16 thus no. of protons is 16 so no. of neutrons is 32-16=16.

no of electron in outermost shell:
distribution of electrons is 2,8,8,18,so on here as x is 16 so no of electron in 1st shell is 2 2nd shell is 8 and outermost shell is 6

electronic configuration is 1s2 2s2 2p6 3s2 3p4

hope you get it

Answer 2

Answer:

of protons is 16 so no. of neutrons is 32-16=16.