The sum of the first n terms of an AP is 2n2+5n, then its nth term is
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Given:
Sum of first n terms of an AP = 2n² + 5n
Substitute n = 1 to find the first term of the AP [ ∵ sum of first 1 terms is nothing but the first term. ]
Hence,
→ a(1) = a = 2(1)² + 5(1)
→ a(1) = a = 2 + 5
→ a = 7
We know that,
Sum of first n terms of an AP = n/2 * [ a + a(n) ]
[ a(n) is the nth term ].
Hence,
→ n/2 * [ 7 + a(n) ] = 2n² + 5n
→ 7 + a(n) = n (2n + 5) * 2/n
→ a(n) + 7 = 4n + 10
→ a(n) = 4n + 10 - 7
→ a(n) = 4n + 3
∵ The nth term of the given AP is 4n + 3.
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