An element x having equivalent mass e forms a general oxide
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Equivalent mass of any element is related to it's molecular mass as
Equivalent mass=Atomic mass/n-factor…(1)
From it's oxide formula MxOy ,it is clear that it's valency or n-factor as both are same for metals is 2y/x because valency of O is 2.
Using equation (1) we get
ATOMIC MASS =n-factor *Equivalent mass
=2yE/x
Hope it helps …
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