An element x with an atomic mass of 81 you has density 10.2 gram centimetre
Answers
To calculate the atomic mass
we have density d= Z*M/a³.NA
Where
Z= no of atom to calculate
M = molecular mass
Na = avagadro constant
It is known that, Avogadro's number, NA= 6.022 ×1023 mol-1
a = edge length
Therefore
Z= d×a³ NA/M
Z=10.2×(4×10^{-8})³×6*10^23/81
Z=8 ( Therefore it is FCC)
Applying the relation, This implies that four atoms of the element are present per unit cell.
Answer:
To calculate the atomic mass
we have density d= Z*M/a³.NA
Where
Z= no of atom to calculate
M = molecular mass
Na = avagadro constant
It is known that, Avogadro's number, NA= 6.022 ×1023 mol-1
a = edge length
Therefore
Z= d×a³ NA/M
Z=10.2×(4×10^{-8})³×6*10^23/81
Z=8 ( Therefore it is FCC)
Applying the relation, This implies that four atoms of the element are present per unit cell.
Explanation: