CBSE BOARD X, asked by shohrab1819, 1 year ago

Sin a-2sin^3a÷2cos^3a-cosa=tan a

Answers

Answered by H1N1H1
3

=sina-2sin^3a/2cos^3a-cosa

=sina(1-2sin^2a)/cosa(2cos^2a-1)

=sina*cos2a/cosa * cos2a

=tana

Similar questions