Question

An element x with an atomic number mass 81 you and density 10.2 gram per centimetre cube if the volume of the unit cell is 2.7 into 10 ki power minus 27 to identify the type of the cubic unit cell

Answer 1

This unit cell will be Primitive cubic cell if it has 1 particle per unit cell .

Solution :

d = 10.2 g / cm3

Edge length = a = 2.7 x 10 ^ -27 cm

M = 81 g / mol

N_A = 6.022 x 10 ^ 23

To find :

Z = ?

d = Z x M / N _A x a^3

Z = d x N_A x a^3 / M

   = 10.2 x 6.02 x 10 ^ 23 ( 2.7 x 10 ^ -27 ) ^ 3 / 81

   = 1.5

Answer 2

Answer:

Solution :

d = 10.2 g / cm3

Edge length = a = 2.7 x 10 ^ -27 cm

M = 81 g / mol

N_A = 6.022 x 10 ^ 23

To find :

Z = ?

d = Z x M / N _A x a^3

Z = d x N_A x a^3 / M

  = 10.2 x 6.02 x 10 ^ 23 ( 2.7 x 10 ^ -27 ) ^ 3 / 81

  = 1.5

Explanation: