Question

An elements A B C D E having atomic no. 18,19,17,9,6 .1) Which element exhibit catenation. 2) Which element has highest electronegativity. 3) Which element can form easily an ionic bond with element C?

Answer 1

Answer:

6, 9,19

Explanation:

carbon,fluorine, potassium

Answer 2

1.Element E exhibit catenation

2.Element D has highest electronegativity

3.Element B can form easily an ionic bond with element C

Explanation:

Atomic number of Argon=18

Atomic number of Potassium=19

Atomic number of Chlorine=17

Atomic number of Florine=9

Atomic number of Carbon=6

Therefore,

Element A is Argon

B-Potassium

C-Chlorine

D-Florine

E-Carbon

1.We know that carbon exhibit catenation.Therefore,

Element E exhibit  catenation.

2.We know the Florine is the most electrongative element.

Element D is florine .

Hence, element D has highest electronegativity.

3.We know that potassium can form ionic bond easily with with element chlorine.

Element B is potassium and element C is chlorine .

Therefore, element B can form easily an ionic bond with element C.

#Learns more:

https://brainly.in/question/11904687