An elephant just drags a 2 tonne log of wood attached to its harness in east direction. In doing so, he requires a force of 1.7 tonnes. Answer the following questions: (i) What is the force of sliding friction? (ii) In which direction sliding force of friction acts?
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1) Sliding friction between the wooden log and the ground is equal to the force applied by the elephant, assuming that the elephant moves with a uniform speed. So Friction = 1.7 * 100 * g = 1700 * 10 = 17 k Newtons.
2) the force of the friction is in the direction west parallel to the ground, opposite to the direction of motion of elephant.
3) we can also find the coefficient of friction between the ground and the wooden log.
μ = 1.7 tonne / 2 tonne = 0.85 that's high
2) the force of the friction is in the direction west parallel to the ground, opposite to the direction of motion of elephant.
3) we can also find the coefficient of friction between the ground and the wooden log.
μ = 1.7 tonne / 2 tonne = 0.85 that's high
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