an elephant weight is 200 kg and foot are of a cross section of 200 CM Standing On The Floor find out the pressure exert by the elephant on the floor
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Answered by
1
pressure=force/area
pressure exerted by one foot = mg/area
P=200×9.8/(.002)²
1m=1/1000km
so 200cm =2m
and 2m=.002km
P=1960/.000004
P=49×10^8 pascal
so by four foot,
196×10^8pascal
pressure exerted by one foot = mg/area
P=200×9.8/(.002)²
1m=1/1000km
so 200cm =2m
and 2m=.002km
P=1960/.000004
P=49×10^8 pascal
so by four foot,
196×10^8pascal
Answered by
0
we know that, pressure=force/area
here pressure exerted by one foot=mg/a^2
200×9.8/(0.002)^2
200cm=0.002km
49×10^8 Pascal
now , force exerted by elephant=49×4×10^8=196×10^8 Pascal
here pressure exerted by one foot=mg/a^2
200×9.8/(0.002)^2
200cm=0.002km
49×10^8 Pascal
now , force exerted by elephant=49×4×10^8=196×10^8 Pascal
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