Areas of two similar triangles are 225 sq.cm. 81sq.cm. If a side of the smaller triangle is 12cm, then find corresponding side of the bigger triangle.
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Answered by
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In the attachment I have answered this problem.
Before solving this problem,
We must know
" The ratio of area of the two similar triangles is equal to ratio of the squares of the corresponding sides" .
See the attachment for detailed solution .
Before solving this problem,
We must know
" The ratio of area of the two similar triangles is equal to ratio of the squares of the corresponding sides" .
See the attachment for detailed solution .
Attachments:
Answered by
181
Hello Dear.
Refers to the attachment for the solution.
Given ⇒
Area of the two similar triangles are 225 cm² and 81 cm².
By using the theorem,
When the two triangles are similar, then the ratio of there areas is equal to the ratio of the square of there corresponding sides.
∴ Area of the ΔABC/Area of the ΔPQR = AB²/PQ²
∴ 225/81 = AB²/12²
⇒ AB² = 225 × 144/81
⇒ AB = √400
∴ AB = 20 cm.
Hence, the corresponding side of the bigger triangle is 20 cm.
Hope it helps.
Refers to the attachment for the solution.
Given ⇒
Area of the two similar triangles are 225 cm² and 81 cm².
By using the theorem,
When the two triangles are similar, then the ratio of there areas is equal to the ratio of the square of there corresponding sides.
∴ Area of the ΔABC/Area of the ΔPQR = AB²/PQ²
∴ 225/81 = AB²/12²
⇒ AB² = 225 × 144/81
⇒ AB = √400
∴ AB = 20 cm.
Hence, the corresponding side of the bigger triangle is 20 cm.
Hope it helps.
Attachments:
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