An elevator cage of mass 900 kg when empty is lifted by means of a wire rope. A 72.5 kg man is standing in it. Assuming the acceleration of the cage as 3 m/sec2, find (i) tension in the wire rope, (ii) the reaction of the cage on the man.
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Answer:
5902.5 N
Explanation:
T= mg
= 900*(9.8)
=8820 N
when accelerating at 3 m/sec2
T= mg- ma
= 8820- (9572.5*3)
= 8820- 2917.5
=5902.5 N
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SOLUTION:
Mass of cage=900 kg
mass of man = 72.5 kg
acceleration due to gravity(g)= 9.8m/s
acceleration of cage( a)= 3m/s
TENSION= mg
tension=900*9.8
= 8820 Nm/s
tension= mg- ma
=8820-(900+72.5)*3
=7702.5
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