An elevator can carry a maximum load of 1800kg (elevator+passengers) is moving up with a constant speed of 2ms^-1 .The fractional force opposing the motion 4000N determine the minimum power delivered by the motor to the elevetor in watts as well as in horse power.
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HEYA MATE HERE U GO.
The down ward force on the elevator is F = mg + Fr = ( 1800× 10 ) + 4000 = 22000N
the motor must supply enough power to balance this force.
Hence, P = F.v = 22000 × 2 = 44000 w =59 hp.
therefore 1hp = 746 w.
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HEYA MATE HERE U GO.
The downward force on the elevator is
F = mg + Ff = [ 1800× 10 ] + 4000 = 22000N
the motor must supply enough power to balance this force.
Hence , P = F. V = 22000 × 2 = 44000 W
= 59 hp there fore (1 hp = 746 w )
The area on the negative side of the force axis has a negative sign.
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