An elevator descend into a mine shaft at the rate of 5meters per minute. What will be its position after quarter an hour. If it begins to descend from 15 meters above the ground, What will be its position after 20Minutes.
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hi
1/4×60=25min.
25×5=125m (+ = upper
( - = lower)
+15-125=110 meters down
5×20=100 meters down the earth
hope it helps
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