Math, asked by kirtiwardhansingh043, 1 month ago

An elevator descend into mine shaft at the rate of 8m/min .If it start descending from 5 m above the ground level how long will it take to reach -195m ?​

Answers

Answered by UnbanirayaMitra
0

Total distance covered from A to C =12+468=480 m

Speed =8 m/min

Therefore, time =

Speed

Total distance covered

time=

8

480

=60 minutes.

Attachments:
Answered by rambhadrapandey21
0

Answer:

min

Step-by-step explanation:

195 + 5 = 200 total distance

rate = 8m/min

time = 200/8 = 25

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