an elevator descends in to a mine shaft at rate of 7m\min if he descent starts from 5m above the ground level ,how long will it take to reach -205 m
Answers
Answered by
10
Answer:
30 mins
Step-by-step explanation:
total distance to be covered=205+5=210 m
rate of descent=7m/min
time taken = distance/speed
210/7
=30 mins
Answered by
1
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