Math, asked by geethashree186, 2 months ago

an elevator descends in to a mine shaft at rate of 7m\min if he descent starts from 5m above the ground level ,how long will it take to reach -205 m​

Answers

Answered by Mohak26
10

Answer:

30 mins

Step-by-step explanation:

total distance to be covered=205+5=210 m

rate of descent=7m/min

time taken = distance/speed

210/7

=30 mins

Answered by Mysteryboy01
1

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