Question

an elevator descends in to a mine shaft at the rate of 5 meter per minute . what will be ots positive after quarter an hour

Answer 1

The elevator transcends the shaft at the rate of 5 meters per minute.
One hour is 60 minutes.
Thus, the position of the elevator after one hour would be = 60 x 5 m
                                                                                            = 300 m

Answer 2

One quarter an hour = 15 mins

Find the position after 15 mins:

Distance descended after 1 min  = 5 metre

Distance descended after 15 mins = 5 x 15

Distance descended after 15 mins = 75 metres

Answer: The elevator will descend 75 metres into the mine shaft after a quarter of an hour.