an elevator descends in to a mine shaft at the rate of 6 m/min. if the elevator starts from 10 m above the ground level, how long will it take to reach -350 m
Answers
Answered by
8
Answer:1 hr
Step-by-step explanation:
350 + 10 = 360
360 divided by 6=60 min = 1hr
Answered by
15
Step-by-step explanation:
Speed of elevator = 6m/minute
Distance that is to be travelled =
- 360( 10 m extra that is above the ground level)
As we know that Speed = distance/time
and we need to find out the time
so, time = distance/speed
= 360/6
= 60 seconds or 1 minute
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