an elevator descends into a mine shaft at rate of 3 metre per minute. What will be its position after one hour. If it begins to descend from 15 metres above the ground. What will be its position after 45 minutes
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speed =3m/min
time=45 mins
distance=45*3
=135m
since he has started above 15m
position after 45mins=135-15
=120m
time=45 mins
distance=45*3
=135m
since he has started above 15m
position after 45mins=135-15
=120m
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