Question

an elevator descends into a mine shaft at rate of 6m/min.if the descent starts from above the ground level how long will it take to reach -350m

Answer 1

Given, Rate of descend of elevator (speed) = 6m/min

Total Distance = 10- (-350) m

= 360 m

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Time taken will be = distance/speed

= 360/6

= 60 min

It will take 60 mins or 1 hour to reach 360 m.

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