an elevator descends into a mine shaft at the 7 metres per minutes . What will be its position after one hours?
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1hour = 60minutes
so in 1hour it descends 7×60 = 420 meters inside
so it's position will be 420m deep
so in 1hour it descends 7×60 = 420 meters inside
so it's position will be 420m deep
Answered by
0
Answer:
1hr=60 mins
Therefore in 1hr, it will descend=> 6 x 70 =420.
Hence, its position will be at -420 m.
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