Math, asked by subodhkumardash5, 6 months ago

An elevator descends into a mine shaft at the rate of 10m/ minute. If the descent starts from 30 m above the ground level, how long will it take to reach -430 m?​

Answers

Answered by SankalpHere
0

Answer:

Time to reach -430m from ground level= -430/10

=43min

time to reach 30m from ground level = 30/10

=3min

Total time to reach -43m from 3m = 43+3=46min

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