Question

An elevator descends into a mine shaft at the rate of 12 m/
min. If
the descent starts from 10 m above the ground level, how long will it take
to reach - 350 m. *​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

first, we need to calculate the total distance the mine shaft is travelling. ie, from 10m above ground to 350 m below ground. so, the total distance is 350m+10m=360m.

now, as the shaft takes 12 m per min speed, we divide 360 by 12. as it is 12m per 1min.

360 divided by 12 = 30.

thus, it will take 30 mins to reach the bottom.

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