Question

An elevator descends into a mine shaft at the rate of 4 whole 3/4 metre per minute. If it begins to descend from 7 whole 1/2 metre above the ground, what will be its position after 18 minutes from the ground?

Pls answer with statements. ​

Answer 1

Answer:

hoper it helps...................................

Step-by-step explanation:

Answer 2

Answer:

-78

Step-by-step explanation:

Convert 19/4 into decimal = 4.75

distance= 4.75*18= 85.5m

15/2=7.5

subtract:

85.5 - 7.5

= 78

as it is below ground level so:

-78

hope it helps..