Question

An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its position after one hour? If it begins to descend from 15 metre above the ground, what will be its position after 45 minutes? ​

Answer 1

Answer:

Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m.

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its position after one hour? = 300 metre

If it begins to descend from 15 metre above the ground, what will be its position after 45 minutes? ​= 210 metre