An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m (means -42 m) below the ground level ?
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Answer:
10 Minutes
Step-by-step explanation:
⇒Total Distance covered = 8-(-42)m = 50m
⇒Speed = 5m/min
⇒Time = Distance/Speed = 50m / 5mM^-1 = 10 Mins = 600 Seconds
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