An elevator descends into a mine shaft at the rate of 5m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 440 m.
Answers
Answered by
6
Answer:
Total distance elevator has to travel = initial position - Final position
= 10 - (-350)
= 10 - 350
= 360 m
Now,
Elevator descends at rates 6m/ mins
Therefore, elevator travels 6m in = 1 m
Elevator travels 1m in = 1/6 minute
Elevator travels 360m in= 1/6 × 360 minutes
= 60 minutes
= 1 hour
Therefore, it will take the elevator 1 hour
Similar questions