an elevator descends into a mine shaft at the rate of 5m per minute. if it begins to descend from 10m above the ground , what will be its position after 30 minutes ?
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Answer:
Step-by-step explanation:
1 minute=5 metres. So 1 hour (60 mins)=60×5=300metres. It started 15 metres above the ground.so the present position under the ground=300-15=285metres. So the elevator is 285metres under the ground.
Answered by
2
Step-by-step explanation:
1 minute=5 metres. So 1 hour (60 mins)=60×5=300metres. It started 15 metres above the ground.so the present position under the ground=300-15=285metres. So the elevator is 285metres under the ground.
1 minute=5 metres. So 1 hour (60 mins)=60×5=300metres. It started 15 metres above the ground.so the present position under the ground=300-15=285metres. So the elevator is 285metres under the ground.
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