Question

Find the value of x and y x+1/2 +y-1/3=9 and x-1/3+y+2=8

Answer 1

your question is not clear,but as I understand this,I had solved
it is better to upload questions in such cases,or mention proper brackets,so that one can easily understand
$\frac{x + 1}{2} + \frac{y - 1}{3} = 9 \\ take \: lcm \\ \frac{3(x + 1) + 2(y - 1)}{6} = 9 \\ 3x + 3 + 2y - 2 = 54 \\ 3x + 2y = 54 - 3 + 2 \\ 3x + 2y = 53 \: \: \: \: \: eq1 \\ \frac{x - 1}{3} + y + 2 = 8 \\ \frac{x - 1 + 3y + 6}{3} = 8 \\ x + 3y + 5 = 24 \\ x + 3y = 24 - 5 \\ x + 3y =1 9 \: \: \: \: \: \: eq2 \\ multiply \: eq2 \: by \: 3 \: and \: subtract \: both \: eq1 \: and \: 2 \\ 3x + 2y = 53 \\ - 3x - 9y = - 57 \\ - 7y = - 4 \\ y = \frac{4}{7} \\ x + 3( \frac{4}{7} ) =1 9 \\ x = 19 - \frac{12}{7} \\ x = \frac{133 - 12}{7} \\ x = \frac{121}{7}$