one member of a Pythagorean triplet is 18. find other two members of the triplet.
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Answered by
22
19^2 =18^2+ 6^2
ac^2 = ab^2 + bc^2
ac= hypotenuse =19
ab = one side =18
bc = 6
other two members are 19 and 6
ac^2 = ab^2 + bc^2
ac= hypotenuse =19
ab = one side =18
bc = 6
other two members are 19 and 6
Answered by
40
Answer:
Step-by-step explanation:
m2-1=18
m2=17
m2-1=18
m=9
Thus,m2-1=81-1=80 and
m2+1=81+1=82
The Pythagorean triplet is
18, 80, 82.
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