Question

show the 9325.768 decimal number in binary BCD and excess 3 codes​

Answer 1

Answer:

super

Step-by-step explanation:

Answer 2

Answer:  binary BCD is $10010001101101.11000100100$

               excess 3 code is  $1100011001011000.101010011011$

Step-by-step explanation:

$932510 = 100100011011012$

By multiplying on the basis of the new translation of numbers from one system to the next, $0.76810 = 0.110001001002$ is used to get a number's fractional component.

Add the entire and fractional parts together here so that:

$100100011011012 + 0.110001001002 = 10010001101101.110001001002$

Consequently, $9325.76810$ equals $10010001101101.110001001002.$

• A non-weighted code used to convey decimal integers is called the excess-3 code (or XS3).
• It is a biased version of the self-complementary binary coded decimal (BCD) code and numeral system.
• It is particularly important for mathematical operations since it solves a problem with the 8421 BCD code that arises when adding two decimal digits whose sum is greater than 9.
• Different algorithms than the typical non-biased BCD or binary positional number system are used for excess-3 arithmetic.

Excess-3 Code Represented

• Excess-3 codes are unweighted and can be created by adding 3 to each digit in a decimal value.
• Each digit is then represented by a 4 bit binary number.
• The steps listed below are used to determine an Excess-3 equivalent of a given binary number:

#SPJ3

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