Math, asked by sailaja12, 1 year ago

An elevator descends into a mine shaft at the rate of 6 meters per minute. if the descends starts from 10m above the ground level, how long will take it to reach - 350 m.​

Answers

Answered by TigerMan28
34

Answer: 1 hour

Step-by-step explanation:

Total distance to cover =10+350

=360 meters

Distance covered in 1 min.=6 meters

Time taken ( in minutes)=360/6

=60 minutes

=1 hour

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Answered by sathsetty
14

Answer:

1 hour

Step-by-step explanation:

6 metres descending for each minute

it is 10 metre above land

in 1minute its height would become -2metre

so it would 350/2 minutes to descend -350 metres

hence its 360/6 making it 60 min or 1hour

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