Question

If x = 7 +4/3 then the value of x + 1/x

is​

Answer 1

${\orange{\overline{\overline{\underline{\underline{\huge{\orange{✧}{\bold{\mathcal{\pink{Answer}}}}}{\orange{✧}}}}}}}}$

$\large{\underline{\underline{\boxed{Given:}}}}$

$x = 7 + 4\sqrt{3}$

$\large{\underline{\underline{\boxed{To\:find:}}}}$

$x + \frac{1}{x}$

$=> \: 7 + 4 \sqrt{3} + \frac{1}{7 + 4 \sqrt{3}}$

$=> \: 7+ 4 \sqrt{3} + \frac{1 \times (7 - 4 \sqrt{3} )}{(7 + 4 \sqrt{3})(7 - 4 \sqrt{3)} }$

$=> \: 7+ 4 \sqrt{3} + \frac{7 - 4 \sqrt{3} }{ {7}^{2} - {(4 \sqrt{3} })^{2} }$

$=> \: 7+ 4 \sqrt{3} + \frac{7 - 4 \sqrt{3} }{ 49 - {(16 (3)})}$

$=> \: 7+ 4 \sqrt{3} + \frac{7 - 4 \sqrt{3} }{ 49 - {(48)} }$

$=> \: 7+ 4 \sqrt{3} + \frac{7 - 4 \sqrt{3} }{1}$

$=> \: 7+ 4 \sqrt{3} + 7 - 4 \sqrt{3}$

$=> 14.$

So, answer is ${\boxed{14}}$.

Answer 2

Given:-

$x = 7 + 4 \sqrt{3}$

To find

$x + \frac{1 }{x}$

The answer will be 14..

Mark me as brainlist please..