Question

An elevator descends into a mine shaft at the rate of 6 meter per minute. If the descent starts

from 20 m above the ground level, how long will it take to reach – 340 m?
Give answer in a statement and be the brainliest and do not forget to write proper equation ​

Answer 1

Answer: 1 hr .

Step-by-step explanation:

Speed of the elevator = 6m/min

We can assume the path of the elevator to be a number line , where the ground level is 0 m , the mine shaft is the negative path and the path above the ground level is the positive path .

Given that the elevator starts its descent from 20 m above the ground level, to reach -340 m , it has to cover a distance of (20 + 340) = 360 m .

Since the speed is 6m/min , time taken to reach -340 m = 360/6 = 60 min or 1 hr .

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Answer 2

Answer:

it took 60 minutes

Step-by-step explanation:

speed of elevator=6 min/hour

total m to desend= 10-[-350]

                             =-360 m

time taken=-360 divided by 6

                 = -60  

thus it took 60 minutes