An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent starts from 10m above the ground level, how long will it take to reach -350m?
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Answer:
here we have to use the formula v=s/t
Step-by-step explanation:
here total distance equals to 10+350=360m
speed equals to 6m/min
so 6m/min=360m/time
time=360/6
time =60minutes
so elevator take 60minutes to reach -350m
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