Question

An elevator descends into a mine shaft at the rate of 6 metres per minute. What will be its position after one hour? If it begins to descend from 20 m above the ground, what will be its position after 35 minutes?

Answer 1

Answer:

An elevator descends into mine shaft at the rate of 6 meters per min.

So,for 1min elevator descends 6meters.

The position of elevator after one hour=>

We know:-

1hr=60mins

60min×6meters=360meters...

But the elevator began to descend from 20meters above

so,

360-20=340meters

It's position after 45mins =45m×6min

=>270meter

The elevator has descended from 15meters above....

so,

270-15meters=225meters....

Hope it helps you....