Math, asked by keshuku17718, 6 months ago

An elevator descends into a mine shaft at the rate of 6 metre per minute. If the descent starts from20
m above the ground level. how long will it take to reach - 340 m?​

Answers

Answered by AshayPrashantPawar
2

Answer:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to travel 10m till the ground, then 350 m more. Thus the elevator would take 1 hour to reach its destination.

Answered by aarush2874
1

Answer:

60 min

Step-by-step explanation:

speed=6m/minute

distance to be covered = 360 m

time taken= 360/6=60min

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