Question

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent starts from the 10m above the ground level, how long will it take to reach-350m. ​

Answer 1

✬ Time = 60 minutes ✬

Explanation:

Given:

• Elevator descends at the rate of –6 m/min.
• Elevator started descending from 10 m above the ground level.

To Find:

• How much time elevator will take to reach –350 m?

Solution: Let it will take x minutes and distance above the ground level be denoted by positive integer and below the ground level by negative.

Here we have

• Initial height of elevator = + 10 m

• Final distance of elevator = –350 m

➟ Total distance to be descended

➟ (−350) − (+10)

➟ –350 – 10 = –360 m

As we know that

★ Distance = Speed × Time ★

$\implies{\rm }$ – 360 = –6 × x

$\implies{\rm }$ – 360/–6 = x

$\implies{\rm }$ 360/6 = x

$\implies{\rm }$ 60 = x

Hence, elevator will take 60 minutes or 1 hour to reach –350 m.

Answer 2

Question

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent starts from the 10m above the ground level, how long will it take to reach -350m.

Solution

We will take the value of -350m as constant. So we will take it as 350m.

Distance = 6m

Time = 1min

Speed = (Distance/Time)

= (6/1) m/min

= 6 m/min

If descent starts from 10m above the ground level, the elevator has to reach

= (350+10)m

= 360m

We know,

Distance = 360m

Speed = 6 m/min

Time = (Distance/Speed)

= (360/6) min

= 60 min

Ans:- It will take 60 minutes to reach a distance of 350m.