Math, asked by mallikarjuna77799, 7 months ago

An elevator descends into a mine shaft at the rate of 6 meters per
starts from 10 m above the ground level, how long will it take to reach - 350 m.​

Answers

Answered by tanishasingh799
6

Answer:

1 hour

Step-by-step explanation:

level at which elevator descends= 10m above the ground level.

Distance elevator descends in 1min= 6m

Time taken to reach -350m = 10+350=360m

                                              = 360/6 = 60min= 1 hour

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