An elevator descends into a mine shaft at the rate of 6 metres per minute. If the descend
starts from 10 m above the ground level, how long will it take to reach -350 m.
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Answer:
1 hour
Step-by-step explanation:
Rate of descent = 6m/min
Starting point = 10m above ground level
Ending point = 350m below ground level
Total distance = 10 + 350 = 360m
Total time taken = 360 ÷ 6 = 60mins
Ans) It would take 1 hour for the elevator to reach -350m.
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