Question

An elevator descends into a mine shaft at the rate of 6 metre per minute.What will be its
position after one hour if it starts to descend from 10 metre above the ground level?

Answer 1

Answer:

7 METERS

Step-by-step explanation:

Answer 2

Answer:

Here, velocity = 6m/minute

Time = one hour = 60 minute

Ok so first we will find how much distance it will descend, and then we will subtract it from 10 meters.

S (distance) = speed × time

                   = 6m/minute × 60 minutes

                   = 360 meters

Now subtract 360meters from 10meters = 10metre - 360meters  = -350 meters

Or, we can say that 350 m below ground level.

Step-by-step explanation:  

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