Question

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the decent starts from 10 m above the ground level, how long will it take to reach – 350 m.

Answer 1

Given,
speed 6m/min.=6m/60s=0.1m/s
Total distance to travel =10+350m=360m
And
Time=
$\frac{distance}{speed}$
=
$\frac{360} {0.1}$
=3600sec=1hr.