An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m.
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Given:
An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level
To find:
how long will it take to reach -350 m.
STEP BY STEP EXPLANATION:
Distance descended is denoted by a negative integer.
Initial height = +10 m
Final depth = -350 m
Total distance to be descended by the elevator = (-350) - (+10) = -360 m
Time taken by the elevator to descend -6 m 1 min
Thus, time taken by the elevator to descend -360 m = (-360) = (-6)
= 60 minutes = 1 hour
∴ it will take 1 hour
Hence verified !
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