Question

two resistance R1=100+3r and R2=200+4r are connected in series. what is their equivalent resistance ​

Answer 1

Explanation:

R=R1+R2+R3 in series

Then R1 is given 100+3r and

R2 is given 200+4r

By taking R=R1+R2

=100+3r+200+4r then

7R=300

R=300/7

R=48.2

Answer 2

Hello Friend!

Here is your answer:

Explanation in step by step:

Given,

Resistant, R1 = ( 100 ± 3 ) Ω

Resistant, R2 = ( 200 ± 4 ) Ω

Equivalent resistance in a series is given by addition of the resistances, ie.

$R_{eq} = R_{1} + R_2 + R_3 + ... R_n$

And combination of resistances tells us to add the resistances,

that means $R_{eq}$ ± ΔR = $(R_{1} + R_2 + R_3 + ... R_n)$  ± Δ( $R_{1} + R_2 + R_3 + ... R_n$ )

Therefore,

Equivalent resistance is ( 100 + 200) ± ( 3 + 4 ) Ω

                                   = ( 300 ± 7 )Ω

Hence you get your answer as ( 300 ± 7 ) Ω

I hope it helps you! Please respond with a thanks if you appreciate my answer.