Math, asked by abhinavpro, 8 months ago

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m?

Answers

Answered by khatribhoomesh2008
1

Answer:

-350×60=21000is correct answer

Answered by Kartikempire
7

Answer:

60 min or 1 hour

Step-by-step explanation:

Rate  of descend = 6m/min

Total distance need to be covered= 10+350=360m

Time=Distance /speeed=360/6 =60min or 1 hour

Pls mark this answer as the Brainliest!!!

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