Question

An elevator descends into a mine shaft at the rate of 6 m/min. If the descents
from 10 m above the ground level, how long will it take to reach - 350 m.​

Answer 1

Answer:

Step-by-step explanation:

as the descent starts from 10 m above the ground and goes upto -350 m,

therefore total distance covered= 360 m

speed= 6 m/min

we know ,

speed = dist./time

or, time = distance/speed

therefore, required time taken =(360/6)min = 60min = 1 hour

Answer 2

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