An elevator descends into a mine Shaft at the rate of 6m/min.if the descends start from 10m above the ground level,how long will it take to reach_350m.
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Answer:
It will take 1 hour to reach -350 m.
Step-by-step explanation:
SOLUTION :
Total distance covered by mine shaft = 10 - (- 350) = 10 + 350 = 360 m
Time taken to cover the distance 6 m = 1 min
Time taken to cover a distance of 1 m = 1/6 min
Time taken to cover a distance of 360 m = (1/6) × 360 = 60 min = 1 hour.
The elevator will reach - 350 m from 10 m in 1 hour.
Hence, it will take 1 hour to reach -350 m.
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