Math, asked by princesssaima2501, 1 year ago

An elevator descends into a mine Shaft at the rate of 6m/min.if the descends start from 10m above the ground level,how long will it take to reach_350m.

Answers

Answered by nikitasingh79
11

Answer:

It will take 1 hour to reach -350 m.

Step-by-step explanation:

SOLUTION :  

Total distance covered by mine shaft = 10 - (- 350) = 10 + 350 = 360 m

Time taken to cover the distance 6 m = 1 min

Time taken to cover a distance of 1 m = 1/6 min

Time taken to cover a distance of 360 m = (1/6) × 360 = 60 min = 1 hour.

The elevator will reach - 350 m from 10 m in 1 hour.

Hence, it will take 1 hour to reach -350 m.

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