Question

An elevator descends into a mine shaft at the rate of 6m/min . If the descent starts from 10m above the ground level ,how long will it take to reach -350m.​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Time\:taken=3600\:sec}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given : }} \\ \tt{: \implies Initial \: velocity(u) = 6 \: m \: {min}^{ - 1}} \\ \\ \tt{ : \implies Distance(s) = 360 \: m} \\ \\ \red{\underline \bold{To \: Find : }} \\ \tt{: \implies Time\:taken =?}$

• According to given question :

$\tt{ \circ \:Initial \: speed = 6 \times \frac{1}{60} = 0.1 \: m/s} \\ \\ \bold{as \: we \: know \: that} \\ \tt{: \implies s = ut + \frac{1}{2} {at}^{2} } \\ \\ \tt{: \implies 360 = 0.1 \times t} \\ \\ \tt{: \implies t = \frac{360}{0.1} } \\ \\ \green{\tt{: \implies t = 3600 \: sec}} \\ \\ \tt{\green{\therefore \: Time \: taken = 3600 \: sec}}$

$\purple{\tt{ \circ \:Some\: formula\:related\:to\:topic }} \\ \pink{\circ\:\tt{v=u+at}} \\ \\\pink{\tt{\circ\: v^{2}=u^{2}+2as}}$

Answer 2

Answer:

$\green{\tt{ \to \: time \: taken =1 \: hour}}$

Step - by - step explanation :

$\bold{we \: know \: that} \\ \tt {\to time = \frac{distance}{speed}} \\ \\ \tt{ \to time = \frac{350 + 10}{6} } \\ \\ \tt{: \to time = \frac{360}{6}} \\ \\ \green{\tt{ \to time = 60 \: min}} \\ \\ \green{\tt{\therefore time \: taken \: = 1 \: hour}}$