An elevator descends into a mine shaft at the rate of 6m/min.If the descent starts from 10m above the ground level, how long will it take to reach -350m. Can anyone explain this question ?
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Answered by
1
Answer:
Step-by-step explanation:
60 minutes as it starts from 10m and go till -350 so 360 in total at 6m/pm.
Answered by
1
Answer:
rate of descend=6m/60sec=1m/10s
total distance to be descended=-10-350= -360
{note here '-' indicated downward direction}
time=d/speed= 360/1/10=3600 sec=1hour
( d is taken + as d cant be - and the minus sign indicates direction in physics)
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